December 13, 2005
-
Update on the C# quirk
It appears that the official C# specifications allow parameters and class members to take on identical names. Disambiguation is achieved through the use of the “this” reference in the method, as follows:
class Foo
{
private int bar;
public Foo(int _bar)
{
bar = _bar;
}
public Print(int bar)
{
System.Console.WriteLine("This is the "bar" parameter: " + bar.ToString());
System.Console.WriteLine("This is the "bar" member: " + this.bar.ToString());
}
}Regardless, this behaviour is not what I experienced while coding my compiler. Using “bar” without the “this” reference resulted in the member instead of the parameter. Therefore, though it is officially legal for a parameter to take on the same name as a class member, I still recommend not to rely on the ambiguity resolution mechanism in Microsoft’s C# compiler. Instead, try to name your parameters differently. If you must, begin all of your parameter names with an underscore (e.g. “_bar” instead of “bar“).
- SwordAngel
